Jobra

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🐞Step 1 of Jobra:AI Debugging RoundsAI-based coding roundsReal-world codebasesAI-powered debugging

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JOBRA · AI DEBUG ROUND (PREVIEW)sum.cpp

// buggy snippet
int total(vector<int>& a, int n) {
    int sum = 0;
    for (int i = 0; i <= n; i++) { // 🐞        sum += a[i];
    }
    return sum;
}

A real codebase. A real bug. You + AI.

Jobra drops you into a broken repo. Find it, fix it, ship it. AI helps you debug like on the job.

Prompt:Correct the loop condition

Tap 'Let Jobra fix it' below to simulate AI debugging...

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1. Reverse String After K Blinks Nobroker - Indian Institute of Technology, Guwahati - Nobroker Interview Question (2025) | Codinzhub

Jobra

HackerRank:LeetCode is dead.→Codinzhub:

🐞Step 1 of Jobra:AI Debugging RoundsAI-based coding roundsReal-world codebasesAI-powered debugging

DSA+AIPreparing you for both.Coming soon.

COMING SOON

JOBRA · AI DEBUG ROUND (PREVIEW)sum.cpp

// buggy snippet
int total(vector<int>& a, int n) {
    int sum = 0;
    for (int i = 0; i <= n; i++) { // 🐞        sum += a[i];
    }
    return sum;
}

A real codebase. A real bug. You + AI.

Jobra drops you into a broken repo. Find it, fix it, ship it. AI helps you debug like on the job.

Prompt:Correct the loop condition

Tap 'Let Jobra fix it' below to simulate AI debugging...

Nobroker Interview Prep

1. Reverse String After K Blinks Nobroker - Indian Institute of Technology, Guwahati

This is a verified interview question from Nobroker. Candidates reporting seeing this problem in recent Online Assessments (OAs) and onsite rounds. Mastering "1. Reverse String After K Blinks Nobroker - Indian Institute of Technology, Guwahati" covers key patterns like Other.

Problem Preview

"**Mode:** On-Campus **Exam Pattern:** 3 codin+20 aptitude+10 cs **OA Date:** 2026-11-11 ## 1. Reverse String After K Blinks Problem statement: You are given a string s and an integer k. In one blink, characters are rearranged simultaneously as follows: - The last character moves between the 1st and 2nd characters. - The second-last character moves between the 3rd and 4th characters. - The third-last character moves between the 5th and 6th characters. - This pattern continues. After performing k blinks, the resulting string is given. Find the original string"

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