Based on the provided images, an explicit question title is not visible on the screen, but the core function is named convertDobFormat.

Here is the exact problem statement transcribed verbatim from the screenshots:

Problem Statement

During account registration, users enter their Date of Birth (DOB) in the format DD/MM/YYYY. Your task is to validate the given DOB string and generate a 6-character user identifier.

If the DOB is valid, print the identifier in the format DDMMYY (day + month + last two digits of year). If the DOB is invalid, print 'Invalid Date'.

Read the input from STDIN and print the output to STDOUT. Do not print arbitrary strings anywhere in the program, as these contribute to the output and test cases will fail.

Input Format:

The only line of input will consist of a string dob, representing the user's Date of Birth in the format DD/MM/YYYY.

Output Format:

The only line output should display a string representing the user identifier in the format DDMMYY, where DD is the two-digit day of birth, MM is the two-digit month of birth, and YY is the last two digits of the year of birth. Also, if the input is invalid, output "Invalid Date".

Sample Input 1:

01/01/1990

Sample Output 1:

010190

Explanation 1: Following the mentioned constraints above and the problem statement, the generated password will be '010190', which will be displayed as an output.

Sample Input 2:

12/07/2005

Sample Output 2:

120705

Explanation 2: Following the mentioned constraints above and the problem statement, the generated password will be '120705', which will be displayed as an output.